Python多行字符串的正确缩进

函数中Python多行字符串的正确缩进是什么？在

    def method():
        string = """line one
line two
line three"""

或者

    def method():
        string = """line one
        line two
        line three"""

还是别的什么？在

在第一个例子中，字符串挂在函数外部看起来有点奇怪

您可能需要使用“”“

def foo():
    string = """line one
             line two
             line three"""

由于新行和空格包含在字符串本身中，因此必须对其进行后处理。如果您不想这样做，并且您有大量的文本，您可能需要将其单独存储在一个文本文件中。如果一个文本文件不适合您的应用程序，并且您不想进行后处理，我可能会选择

def foo():
    string = ("this is an "
              "implicitly joined "
              "string")

如果要对多行字符串进行后处理，以去掉不需要的部分，则应考虑textwrapmodule or the technique for postpprocessing docstrings presented indef trim(docstring):
if not docstring:
return ''
# Convert tabs to spaces (following the normal Python rules)
# and split into a list of lines:
lines = docstring.expandtabs().splitlines()
# Determine minimum indentation (first line doesn't count):
indent = sys.maxint
for line in lines[1:]:
stripped = line.lstrip()
if stripped:
indent = min(indent, len(line) - len(stripped))
# Remove indentation (first line is special):
trimmed = [lines[0].strip()]
if indent < sys.maxint:
for line in lines[1:]:
trimmed.append(line[indent:].rstrip())
# Strip off trailing and leading blank lines:
while trimmed and not trimmed[-1]:
trimmed.pop()
while trimmed and not trimmed[0]:
trimmed.pop(0)
# Return a single string:
return '\n'.join(trimmed)