- 问题:
-
函数中Python多行字符串的正确缩进是什么?在
def method():
string = """line one
line two
line three"""或者
def method():
string = """line one
line two
line three"""还是别的什么?在
在第一个例子中,字符串挂在函数外部看起来有点奇怪
- 答案:
-
您可能需要使用
“”“
def foo():
string = """line one
line two
line three"""由于新行和空格包含在字符串本身中,因此必须对其进行后处理。如果您不想这样做,并且您有大量的文本,您可能需要将其单独存储在一个文本文件中。如果一个文本文件不适合您的应用程序,并且您不想进行后处理,我可能会选择
def foo():
string = ("this is an "
"implicitly joined "
"string")如果要对多行字符串进行后处理,以去掉不需要的部分,则应考虑
textwrap
module or the technique for postpprocessing docstrings presented indef trim(docstring):
if not docstring:
return ''
# Convert tabs to spaces (following the normal Python rules)
# and split into a list of lines:
lines = docstring.expandtabs().splitlines()
# Determine minimum indentation (first line doesn't count):
indent = sys.maxint
for line in lines[1:]:
stripped = line.lstrip()
if stripped:
indent = min(indent, len(line) - len(stripped))
# Remove indentation (first line is special):
trimmed = [lines[0].strip()]
if indent < sys.maxint:
for line in lines[1:]:
trimmed.append(line[indent:].rstrip())
# Strip off trailing and leading blank lines:
while trimmed and not trimmed[-1]:
trimmed.pop()
while trimmed and not trimmed[0]:
trimmed.pop(0)
# Return a single string:
return '\n'.join(trimmed)